0(x)=-16x^2+52x^2

Solution for 0(x)=-16x^2+52x^2 equation:

0(x)=-16x^2+52x^2

We move all terms to the left:

0(x)-(-16x^2+52x^2)=0

We add all the numbers together, and all the variables

-(-16x^2+52x^2)+x=0

We get rid of parentheses

16x^2-52x^2+x=0

We add all the numbers together, and all the variables

-36x^2+x=0

a = -36; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-36)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-36}=\frac{-2}{-72}
=1/36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-36}=\frac{0}{-72}
=0
$